Re: Random pick

On Mon, 25 Jan 2010, Karl DeSaulniers wrote:

Thank you for this as well. Question? What part is "in_array" playing? Is it comparing $req_user_level to array()? Because the text "Guest", etc.. is not in $req_user_level on the database. In other words, is it checking the value of $req_user_level to see if "Guest" is in it?

Sorry, I missed the question mark. in_array isn't appropriate here. The previous poster has it right, assuming $req_user_level is an integer of 0..9. $levels = array("Guest", "Regular User", 'Intl. User', ...)

 // the array is   0    ,      1        ,       2     , ...)

Going a little further:

    if (!empty($levels[$req_user_level])) {  // is both set and doesn't evaluate to false
        echo "The user is a {$levels[$req_user_level]}.\n";
    } else {
        //  The $req_user_level was not a valid level.
        echo "The returned req_user_level was not valid.\n";
    }

Which would output, if $req_user_level was 1 (one):

    The user is a Regular User.

Then you know you have a valid user level. Careful though -- sometimes 0 will be returned on a failure, depending on your SQL. Beckman ---------------------------------------------------------------------------

Peter Beckman                                                  Internet Guy
beckman@angryox.com                                 http://www.angryox.com/

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