#39574 [Opn->Bgs]: ZipArchive::renameName won't accept variables for file names
| From: | damon dot dean at revcube dot com | Date: | Tue, 21 Nov 2006 22:48:27 +0000 |
| Subject: | #39574 [Opn->Bgs]: ZipArchive::renameName won't accept variables for file names | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-105273@lists.php.net to get a copy of this message | ||
ID: 39574
User updated by: damon dot dean at revcube dot com
Reported By: damon dot dean at revcube dot com
-Status: Open
+Status: Bogus
Bug Type: Scripting Engine problem
Operating System: Mac OS X
PHP Version: 5.2.0
New Comment:
I'm going to retract this. I'm not sure that I should even be
trying to call this function and renaming before extracting
the file.
Previous Comments:
------------------------------------------------------------------------
[2006-11-21 22:23:59] damon dot dean at revcube dot com
Description:
------------
I'm not sure if this is a bug, or by design, but this function
works differently than others I've seen in PHP. No matter I
try, if I try to pass a file name as a variable to
ZipArchive::renameName, it prints the name of the variable as
the filename, rather than the value of the variable.
Reproduce code:
---------------
<?php
$logDateTime = date('Y_m_d_H_i_s');
$CSVFileName = "HGN_GGL"._."$logDateTime".".csv";
$zip = new ZipArchive;
if ($zip->open('./reports/report-csv.zip') === TRUE) {
//Also tried '' and ""with function below
$zip->renameName('report.csv', $CSVFileName);
$zip->extractTo('./reports');
echo "Yay!";
} else {
echo "Boo";
}
?>
Expected result:
----------------
I would expect it to output a file with a name along the lines
of this:
HGN_GGL_2006_11_21_14_17_07.csv
Actual result:
--------------
Instead, it produces a file name like this:
$CSVFileName
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=39574&edit=1