#41389 [Opn->Bgs]: unknow
ID: 41389
Updated by: johannes@php.net
Reported By: bskandmon at hotmail dot com
-Status: Open
+Status: Bogus
Bug Type: MySQL related
Operating System: unknow
PHP Version: 5.2.2
New Comment:
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to
report
a bug at http://bugs.php.net/how-to-report.php
mysql_error() just passed the original error message from the database.
The function doesn't know what you are doing with the returned value.
(logging ...) So no escaping can be done.
As a general notice: If the user can generate a MySQL error you have
most likely a bigger problem than XSS: SQL injection.
Previous Comments:
------------------------------------------------------------------------
[2007-05-14 19:57:17] bskandmon at hotmail dot com
Description:
------------
I'm french and I'm 15, so excuse me for my verry verry bad english.
I've found an xss fail in mysql_error(). You've just to do a synthax
error (whit " in my example) and write your script after the ".
Reproduce code:
---------------
$var = '"<script>alert(\'Hi ! Xss discovered !\')</script>';
$rep = mysql_query('SELECT pseudo FROM membres where pseudo =
"'.$var.'"');
if (!$rep)
{
echo '<br><b>Transmettre aux administrateurs : (via la page contact ou
par mp) '.mysql_error().'</b>';
}
else
{
return $rep;
}
------------------------------------------------------------------------
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