Bug #17720 Updated: "Cannot redeclare function_name previously declared in ..." is bogus

ID: 17720 Updated by: per_hekansson@hermes.ics.lu.se Reported By: bdgridly@mailbolt.com Status: Critical Bug Type: Scripting Engine problem Operating System: Win2k and Apache PHP Version: 4.2.1 New Comment: I have had a similar problem. I think it has to do with case sensitivity in the include once function. The inclusion is not case sensitive but the check if the script is allready included is. The file name was sqlFunctions.inc include_once("sql\sqlFunctions.inc"); -- no problem include_once("sql\sqlfunctions.inc"); -- error /Per Previous Comments: ------------------------------------------------------------------------ [2002-06-23 21:11:12] phpbugs@soupisgoodfood.network I'm also experiencing this problem. I have tried to rearange things thinking it was my code (I'm a newbie). All scripts for this particular site have one include() with functions decalred inside. Some have 2 includes with functions declared. They all work fine. For some reason, one script with 2 includes for functions is giving this error (it's template is different). I still can't figure out what's causing it. But what's even stranger is, if I re-arrange one include (put it at the top, which shouldn't cause any problems) my browser gives me a "Attempt to load URL:foobar failed" error instead of PHP giving me the "Cannot redeclare..." error. PHP and Apatche carry on just fine on other pages after this happens (IE, it isn't crashing anything). If anyone finds out more about this, I'd really appeciate it if you could contact my ASAP (don't forget to change the .network to .net on my address). Thanks. Justin. ------------------------------------------------------------------------ [2002-06-12 10:31:56] bdgridly@mailbolt.com >include_once() is the problem here. It should propably >not include the current script run. Yes, the "include_once("main.php")" is causing the problem because it confuses the interpreter into thinking SystemTest() is declared twice. If I remove the "include_once("main.php")", it will work. But this is a workaround. What happens if test1() is also called from test2.php? How is test1() going to load NewTest() in main.php if there is no include for main.php? I am pretty sure this worked in PHP 4.06 because it stopped working yesterday when I installed PHP 4.2.1. The only way I see of correcting it is to go back to 4.06. :( ------------------------------------------------------------------------ [2002-06-12 09:18:29] sniper@php.net include_once() is the problem here. It should propably not include the current script run.. ------------------------------------------------------------------------ [2002-06-11 21:48:42] bdgridly@mailbolt.com It is possible in PHP 4.2.1 to confuse the interpreter into thinking a function had been previously declared when in fact it is the same function. I'm sure this used to work in PHP 4.01. I installed 4.2.1 today and now it complains. Sample test program: File: MAIN.PHP <?PHP include_once("test1.php"); function SystemTest() //<<-- Error: SystemTest() previously declared in Main.Php at line 4 { Test1(); } function NewTest() { echo "New Test"; } SystemTest(); ?> File: Test1.PHP <?PHP include_once("main.php"); function test1() { echo "This is Test1()<BR>"; NewTest(); } ?> If you run Main.PHP, it will generate an error because it thinks SystemTest was previously declared and it gives as the line number of the "other" definition as the line # where the error occurred. So it is really pointing to itself. In this simple example I could get rid of the "include_once("main.php")" and it will start to work. But what if Test1 is also called from test2.php. Then SystemTest() it won't find NewTest() that is in Main.Php. Can this be fixed? TIA Brent (e-mail me if you can with an explanation if it is operator error<g>) ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=17720&edit=1