#44654 [Asn->Csd]: Syntax error for #
ID: 44654
Updated by: nlopess@php.net
Reported By: xuefer at gmail dot com
-Status: Assigned
+Status: Closed
Bug Type: Compile Failure
Operating System: *
PHP Version: 5.3CVS-2008-04-06 (CVS)
Assigned To: nlopess
New Comment:
This bug has been fixed in CVS.
Snapshots of the sources are packaged every three hours; this change
will be in the next snapshot. You can grab the snapshot at
http://snaps.php.net/.
Thank you for the report, and for helping us make PHP better.
Previous Comments:
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[2008-04-07 17:51:50] scottmac@php.net
It is.
http://lxr.php.net/source/ZendEngine2/zend_language_scanner.l#2155
Was added during the conversion to handle the shebang, it may not be
quite working as expected though.
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[2008-04-07 17:04:09] xuefer at gmail dot com
tested with cli and fastcgi web (not cgi), so not a shebang problem.
we're talking about this bug at mailinglist and looks like it's
relatived to re2c lexer changes recentl
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[2008-04-07 08:05:55] kalle@php.net
Are you running PHP in CGI mode? If so then it might be the CGI shebang
doing funky stuff after my guessings atleast in 2.php even though it
isn't #! as shebangs normally are...
For the CLI example I think (from memories) that you can't break in and
out of php with the -r option.
------------------------------------------------------------------------
[2008-04-06 14:19:03] xuefer at gmail dot com
Description:
------------
$ php -r 'if (1) { ?>#<?php }'
Parse error: syntax error, unexpected $end in Command line code on line
1
note that you cannot reproduce with ?> #<?php (with a space before #
Reproduce code:
---------------
1.php
<?php if (1) { ?>#<?php } ?>
2.php
#<?php echo 1; ?>
#<?php echo 1; ?>
expected:
#1#1
actual:
#<?php echo 1; ?>
#<?php echo 1; ?>
Expected result:
----------------
used to work in php5.2 IIRC and echo # character
Actual result:
--------------
Parse error: syntax error, unexpected $end in Command line code on line
1
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