#45642 [Bgs]: parse problem on preg_replace

ID: 45642 User updated by: zionwilson at gmail dot com Reported By: zionwilson at gmail dot com Status: Bogus Bug Type: PCRE related Operating System: Windows Vista x64 Ultimate PHP Version: 5.2.6 New Comment: thanks felipe, you're really helpful Previous Comments: ------------------------------------------------------------------------ [2008-07-27 23:43:26] felipe@php.net Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php Note: $cr4 = intval('\\3')*intval('\\2')+intval('\\1'); and others... This code obviously will be processed before preg_replace. It isn't a string, but pure PHP code. It should be like: $cp4 = "/([1-9][0-9]*)\s([1-9][0-9]*)\s([1-9][0-9]*)/e"; $cr4 = "intval('\\3')*intval('\\2')+intval('\\1')"; Thanks. ------------------------------------------------------------------------ [2008-07-27 21:00:31] zionwilson at gmail dot com Description: ------------ for the function preg_replace() i guess it does comparison and other operation before parse the result from '\\3', '\\2', '\\1' when use a 'general' match pattern like ([1-9][0-9]*) hence inval() won't work because for string '\\3' or '${3}' the result is always zero. however 'modifier-like' match pattern like \d, works well. so what is the fast work around if i need php to parse "\\1" before doing any operation like inval(), or comparison, at the moment? Reproduce code: --------------- <? $c1 = "2 4 8"; $cp1 = "/(\d)\s(\d)\s(\d)/e"; $cr1 = "'\\3*\\2+\\1='.(('\\3')*('\\2')+('\\1'))"; $c2 = "2 4 8"; $cp2 = "/([1-9][0-9]*)\s([1-9][0-9]*)\s([1-9][0-9]*)/"; $cr2 = "'\\3*\\2+\\1='.(('\\3')*('\\2')+('\\1'))"; $c3 = "2 4 8"; $cp3 = "/([1-9][0-9]*)\s([1-9][0-9]*)\s([1-9][0-9]*)/"; $cr3 = "'\\3*\\2+\\1='.(('\\3')*('\\2')+('\\1'))"; $c4 = "2 4 8"; $cp4 = "/([1-9][0-9]*)\s([1-9][0-9]*)\s([1-9][0-9]*)/"; $cr4 = intval('\\3')*intval('\\2')+intval('\\1'); $c5 = "2 4 8"; $cp5 = "/([1-9][0-9]*)\s([1-9][0-9]*)\s([1-9][0-9]*)/"; $cr5 = ('\\3' == '${3}' ? '${3}' . ' equals to ' . '\\3' : '${3}' . 'not equals to' . '\\3'); echo (preg_replace($cp1,$cr1,$c1)); echo ("<br>"); echo (preg_replace($cp2,$cr2,$c2)); echo ("<br>"); echo (preg_replace($cp3,$cr3,$c3)); echo ("<br>"); echo (preg_replace($cp4,$cr4,$c4)); echo ("<br>"); echo (preg_replace($cp5,$cr5,$c5)); ?> Expected result: ---------------- 8*4+2=34 8*4+2=34 8*4+2=34 34 8equals to8 Actual result: -------------- 8*4+2=34 '8*4+2='.(('8')*('4')+('2')) '8*4+2='.(('8')*('4')+('2')) 0 8not equals to8 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=45642&edit=1