Bug #18070 Updated: INSERT failure

ID: 18070 Updated by: Akujin11@yahoo.com Reported By: Akujin11@yahoo.com -Status: Feedback +Status: Open Bug Type: MySQL related Operating System: Windows XP PHP Version: 4.2.0 New Comment: i made the change you suggested, it still refuses to add data. by the way, the Akuma you see there is from my database, so you can see that the connection is working. Previous Comments: ------------------------------------------------------------------------ [2002-07-04 09:09:31] sniper@php.net Try changing that $PHP_SELF to $_SERVER['PHP_SELF'] as that didn't work.. ------------------------------------------------------------------------ [2002-07-04 00:12:48] Akujin11@yahoo.com thats the POINT. it doesn't work right. it can call data from my database (so i know the connection works) but it refuses to insert anything. the source is as follows: <html> <head> <title>Character Entry Form</title> </head> <body> <?php mysql_connect("localhost", "root") or die("Could not establish a connection to the database."); mysql_select_db("MvC2") or die("Could not select the given database."); function submit_values($char_name, $char_game, $char_alias) { $insert_query = "INSERT INTO characters VALUES ('$char_name', '$char_game', '$char_alias');"; mysql_query($insert_query) or die(mysql_error()); } function results() { ?> <table width=400 border=1> <tr> <td width=150>Name</td> <td width=50>Game</td> <td width=150>Alias</td> </tr> <? $result_query = "SELECT * FROM characters ORDER BY name;"; $result_value = mysql_query($result_query) or die(mysql_error()); $x = 0; while ($row = mysql_fetch_array($result_value)) { if(($x % 2) == 0) { $c = "#cccccc"; } else { $c = "#FFcccc"; } ?> <tr> <td bgcolor="<?= $c; ?>"><?= $row["name"]; ?></td> <td bgcolor="<?= $c; ?>"><?= $row["game"]; ?></td> <td bgcolor="<?= $c; ?>"><?= $row["c_alias"]; ?></td> </tr> <? $x++; } ?> </table> <? } function show_input() { ?> <form method=post action="<?php $PHP_SELF ?>"> <table width=400 rules="none"> <tr> <td>Name:</td> <td><input type="text" name="character"> </tr> <tr> <td>Game:</td> <td><input type="text" name="game"> </tr> <tr> <td>Alias:</td> <td><input type="text" name="alias"> </tr> <tr> <td><input type="submit" name="submit" value="insert character"></td> <td><input type="reset" value="reset"></td> </tr> </table> </form> <? } if ($submit) { $insert_query = "INSERT INTO characters VALUES ('Akuma', 'game', 'alias');"; mysql_query($insert_query) or die(mysql_error()); show_input(); results(); } else { show_input(); results(); } ?> </body> </html> see what you can make of it, but i'm telling you the problem lies not with the code (which i personally wrote, and that worked untill my upgrade), but insted with the new release. if you look at the number of people that are having this same problem you will see that the evidence does point that way. ------------------------------------------------------------------------ [2002-07-03 21:49:59] sniper@php.net That example of yours doesn't work quite right.. Where's the source for it? (the given url..) ------------------------------------------------------------------------ [2002-06-30 07:05:38] Akujin11@yahoo.com i downloaded and installed 4.2.1 and it still does not work. Here, see the file for yourself and see if you can add any input: http://24.127.136.211/enter_char.php ------------------------------------------------------------------------ [2002-06-30 06:47:38] derick@php.net Try the latest version (4.2.1) first ------------------------------------------------------------------------ The remainder of the comments for this report are too long. To view the rest of the comments, please view the bug report online at http://bugs.php.net/18070 -- Edit this bug report at http://bugs.php.net/?id=18070&edit=1