#47903 [Ver->Asn]: "@" operator does not work with string offsets (PHP_5_2 only!)

ID: 47903 Updated by: jani@php.net Reported By: cFreed at orange dot fr -Status: Verified +Status: Assigned Bug Type: Scripting Engine problem Operating System: * PHP Version: 5.2.9 -Assigned To: +Assigned To: felipe New Comment: Felipe, this same (?) issue was reported in bug #39018 and was supposed to be closed too..was the fix omitted from PHP_5_2 branch? Previous Comments: ------------------------------------------------------------------------ [2009-04-06 08:34:36] kalle@php.net Verified in the PHP_5_2 branch only, PHP_5_3 and HEAD does not produce this, reclassified ------------------------------------------------------------------------ [2009-04-05 19:05:35] cFreed at orange dot fr Description: ------------ A case where the error-control operator @ does NOT work, despite of what the manual says. Reproduce code: --------------- --- From manual page: language.operators.errorcontrol --- The manual says: "A simple rule of thumb is: if you can take the value of something, you can prepend the @ operator to it." This is not always true. As shown by the example given, this works, assuming $cache IS AN ARRAY: <?php $value = @$cache[$key]; // will not issue a notice if the index $key doesn't exist. ?> But it does not work if $cache IS A STRING, and $key is an integer higher than strlen($cache)-1. in other words: <?php $str='abc'; $value=@$str[5]; // will issue the notice "Uninitialized string offset 5 in...". ?> ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=47903&edit=1