#50191 [Bgs]: $SERVER['argv'] not working as expected

ID: 50191 User updated by: ppass at hotmail dot fr Reported By: ppass at hotmail dot fr Status: Bogus Bug Type: URL related Operating System: Windows PHP Version: 5.2.11 New Comment: I don't believe this. The manual says: << Array of arguments passed to the script. When the script is run on the command line, this gives C-style access to the command line parameters. When called via the GET method, this will contain the query string. >> "When the script is run on the command line" means that COMMAND line is not the only way. Anyway, it is possible to call from PHP. Still, the problem is not solved. Previous Comments: ------------------------------------------------------------------------ [2009-11-16 16:20:34] jani@php.net This variable is meant for COMMAND line only. ------------------------------------------------------------------------ [2009-11-16 16:06:35] ppass at hotmail dot fr Description: ------------ I sometimes use URLs with several arguments. The value of some of arguments are urlencoded, so a space will be translated to a + sign. The problem is that $SERVER['argv'] seems to interpret this + sign by as a separator. Reproduce code: --------------- File: argv_behaviour.php <?php Echo "<br/>List of arguments: (".$_SERVER['argv'][0].")"; ?> Expected result: ---------------- When launching argv_behaviour.php?arg1=aa&arg2=b+c&arg3=dd I expect to see List of arguments: (arg1=aa&arg2=b+c&arg3=dd) Actual result: -------------- but I get List of arguments: (arg1=aa&arg2=b) I get the wrong number of arguments and truncated value for some of them. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=50191&edit=1