Bug #52133 [Opn]: Functions cannot return an argument passed by reference as reference

From: Date: Tue, 22 Jun 2010 22:51:13 +0000
Subject: Bug #52133 [Opn]: Functions cannot return an argument passed by reference as reference
References: 1  Groups: php.bugs 
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Edit report at http://bugs.php.net/bug.php?id=52133&edit=1

 ID:               52133
 User updated by:  bschussek at gmail dot com
 Reported by:      bschussek at gmail dot com
 Summary:          Functions cannot return an argument passed by
                   reference as reference
 Status:           Open
 Type:             Bug
 Package:          Scripting Engine problem
 Operating System: Linux Ubuntu 10.04
 PHP Version:      5.3.2

 New Comment:

In my last comment I dumped first $b and then $c, so the output hasn't
changed 
from PHP 5.3.2.


Previous Comments:
------------------------------------------------------------------------
[2010-06-23 00:48:36] bschussek at gmail dot com

Sorry, but the test script produces still the wrong output for me.

$ php -v
PHP 5.3.3-dev (cli) (built: Jun 23 2010 00:45:57) 
Copyright (c) 1997-2010 The PHP Group
Zend Engine v2.3.0, Copyright (c) 1998-2010 Zend Technologies
    with Xdebug v2.0.5, Copyright (c) 2002-2008, by Derick Rethans

$ php test.php
string(6) "foobar"
string(6) "fozbar"

------------------------------------------------------------------------
[2010-06-23 00:29:01] johannes@php.net

Please try using this snapshot:

  http://snaps.php.net/php5.3-latest.tar.gz
 
For Windows:

  http://windows.php.net/snapshots/

------------------------------------------------------------------------
[2010-06-21 13:56:07] bschussek at gmail dot com

Description:
------------
PHP does not behave as expected when passing arguments by reference into
a 
function that are passed out again by reference.

IMO, the below test script should behave equivalently to the following
code 
(which produces the expected result):

$b = 'foobar';
$a =& $b;
$c =& $a;
$c[2] = 'z';

var_dump($c);
var_dump($b);

Test script:
---------------
function &ref(&$a)
{
  return $a;
}

$b = 'foobar';
$c = ref($b);
$c[2] = 'z';

Expected result:
----------------
string 'fozbar' (length=6)
string 'fozbar' (length=6)

Actual result:
--------------
string 'fozbar' (length=6)
string 'foobar' (length=6)


------------------------------------------------------------------------



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