Bug #53135 [Opn->Bgs]: I have PHP >5 and have a call-time pass-by-reference problem

Edit report at http://bugs.php.net/bug.php?id=53135&edit=1 ID: 53135 Updated by: aharvey@php.net Reported by: josh dot richard at gmail dot com Summary: I have PHP >5 and have a call-time pass-by-reference problem -Status: Open +Status: Bogus Type: Bug Package: Sockets related Operating System: CentOS 5.5 PHP Version: Irrelevant Block user comment: N New Comment: You shouldn't specify &$errno and &$errstr with the & operator; simply providing $errno and $errstr will work fine. Further explanation: http://php.net/language.references.pass Not a bug; closing. Previous Comments: ------------------------------------------------------------------------ [2010-10-22 10:23:10] josh dot richard at gmail dot com Description: ------------ I'm trying to use fsocketopen() to test a server connection- to see if it's online or offline. Even the manual says I can call it like this: $connection = fsockopen("www.example.com", 80, $errno, $errstr, 30); However, I get this warning message when doing so: PHP Warning: Call-time pass-by-reference has been deprecated - argument passed by value; If you would like to pass it by reference, modify the declaration of fsockopen(). If you would like to enable call-time pass-by-reference, you can set allow_call_time_pass_reference to true in your INI file. However, future versions may not support this any longer. Is there another way to declare fsocketopen()??? I see nothing about this!! Test script: --------------- <? // This value is either example.com OR example.com:port $serverAddress = $_POST[server]; @list($addr,$port)= explode (':', $serverAddress); if (empty($port)) { $port = 80; } // Test the server connection $connection = @fsockopen($addr, $port, &$errno, &$errstr, 30); if (!$connection) { echo $addr . ":" . $port . " is currently DOWN"; } else { echo $addr . ":" . $port . " is currently UP"; } ?> Expected result: ---------------- Not expecting any warning!! Actual result: -------------- Where does this warning come from? I've called fsocketopen() like this for years!! ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/bug.php?id=53135&edit=1