Edit report at http://bugs.php.net/bug.php?id=5889&edit=1
ID: 5889
Comment by: joshua at gmail dot com
Reported by: tomwk at audiogalaxy dot com
Summary: pack() does not take arrays
Status: Wont fix
Type: Feature/Change Request
Package: Feature/Change Request
Operating System: Redhat Linux
PHP Version: 4.0.1pl2
Block user comment: N
Private report: N
New Comment:
Yes, it WILL be implemented
Previous Comments:
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[2004-06-14 10:49:20] magnus@php.net
This will not be implemented.
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[2000-08-01 10:22:25] stas@php.net
Well, functions args work differently in perl and PHP. Maybe we need
some "array" type of pack modifier, because PHP does not convert
function arguments to array. Though, you can write a wrapper function
using func_get_args() and func_num_args() for this.
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[2000-08-01 09:51:18] tomwk at audiogalaxy dot com
I have an application that writes data across our network
to another program. Most of the data consists of integer arrays. I'm
currently doing this in a very simple manner,
using something like this:
for( $i = 0; $i < $numInts; $i++ ) {
fwrite( $fd, pack( "N", $ints[ $i ] ) );
}
However, this results in a very large number of calls to
fwrite, which is bad for performance. I made the routine
about 3 times faster by doing something like this:
fwrite( $fd, pack( "N10"
$ints[ $i + 0 ],
$ints[ $i + 1 ],
$ints[ $i + 2 ], ///.. and so on,
However, it would be really great if pack could take an array as one of
it's arguments. I believe this is the way
Perl behaves, but when I try:
$data = array( 10, 123 );
$buf = pack( "N*", $data );
$valArray = unpack( "N*", $buf );
while( list( $key, $val ) = each( $valArray ) ) {
echo "$key -> $val\n";
}
the only output I get is:
1 -> 1
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Edit this bug report at http://bugs.php.net/bug.php?id=5889&edit=1