#10102 [Ana]: need a better error message when argument to empty() isn't a variable
| From: | sander@php.net | Date: | Thu, 08 Aug 2002 13:24:24 +0000 |
| Subject: | #10102 [Ana]: need a better error message when argument to empty() isn't a variable | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-16267@lists.php.net to get a copy of this message | ||
ID: 10102
Updated by: sander@php.net
-Summary: Parse error
Reported By: pulstar@mail.com
Status: Analyzed
Bug Type: Feature/Change Request
Operating System: Windows 98 4.10 english
PHP Version: 4.0.4
New Comment:
update summary
Previous Comments:
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[2001-04-02 05:06:17] hholzgra@php.net
empty() will only accept variables,
no expressions
the error message is a little misleading,
do i move this to feature requests:
"have a better error message when argument to
empty() isn't a variable"
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[2001-04-01 19:05:21] pulstar@mail.com
Parse error: parse error, expecting `')''
in c:\site\home\news.php on line 21
Line 21: if(!empty($news->getField(url)))
Line 22: echo $news->getField(url);
What is wrong in this line?
I changed it to:
$thing=$news->getField(url);
if(!empty($thing))
echo $news->getField(url);
Now, it works fine. Weird...
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Edit this bug report at http://bugs.php.net/?id=10102&edit=1