Bug #61188 [Opn->Nab]: Assignment changes order of evaluation of binop expression

Edit report at https://bugs.php.net/bug.php?id=61188&edit=1 ID: 61188 Updated by: rasmus@php.net Reported by: antickon at gmail dot com Summary: Assignment changes order of evaluation of binop expression -Status: Open +Status: Not a bug Type: Bug Package: Variables related Operating System: linux PHP Version: 5.3.10 Block user comment: N Private report: N New Comment: You are outsmarting yourself here. Look at your brackets. $a == ($a=4) So we do the bracketed expression first: $a=4 which sets $a to 4 obviously and returns the value 4. So what are we left with? $a == 4 But what is $a at this point? Well, it is 4 of course, because we just set it. So we have: 4 == 4 If you can find a language where this expression doesn't return true, regardless of the initial value of $a, then you should file a bug against that language. Previous Comments: ------------------------------------------------------------------------ [2012-02-26 17:54:18] antickon at gmail dot com Description: ------------ An assignment expression can change the order of operation for == and != (and possibly other binops) Test script: --------------- <?php $a = 3; var_dump( $a == ( $a = 4 ) ); Expected result: ---------------- bool(false) evaluation of $a == ( $a = 4 ) should be as follows: left side of the comparison is evaluated (evaluates to 3) right side of the comparison is evaluated (4 is assigned to $a, evaluates to 4) 3 == 4 finally evaluates to false Actual result: -------------- bool(true) ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=61188&edit=1