Bug #47202 [Wfx->ReO]: FTP fopen wrapper and # in file names
Edit report at https://bugs.php.net/bug.php?id=47202&edit=1
ID: 47202
Updated by: langemeijer@php.net
Reported by: smlerman at gmail dot com
Summary: FTP fopen wrapper and # in file names
-Status: Wont fix
+Status: Re-Opened
Type: Bug
Package: Streams related
Operating System: *
PHP Version: 5.2.8
Block user comment: N
Private report: N
New Comment:
I was able to fix the problem for the ssh2 wrapper. I assume it can be fixed for
ftp too. See bug #59794
Previous Comments:
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[2009-03-03 07:05:27] hradtke@php.net
The php_url_parse_ex function intentionally strips the # character from the filename. I did some
research and see that this was done to fix Bug #31705 (http://bugs.php.net/bug.php?id=31705).
From http://www.w3.org/Addressing/URL/4_URI_Recommentations.html
:
The hash ("#", ASCII 23 hex) character is reserved as a delimiter to separate the URI of
an object from a fragment identifier.
This behavior is intentional.
------------------------------------------------------------------------
[2009-01-23 15:22:38] smlerman at gmail dot com
Description:
------------
It seems that the FTP fopen wrapper truncates file names when it encounters a pound sign (#). The
FTP server's log shows a request for "file".
I have tried replacing the # with %23 (the result of urlencode), but the server sees that as a
request for "file%231.txt".
Reproduce code:
---------------
// Use fopen wrapper
$data = file_get_contents("ftp://username:password@ftp.example.com/file
#1.txt");
var_dump(strlen($data));
// Use ftp_* functions
$conn = ftp_connect('ftp.example.com');
ftp_login($conn, 'username', 'password');
ftp_get($conn, 'C:\\test.txt', 'file#1.txt', FTP_BINARY);
var_dump(filesize('C:\\test.txt'));
Expected result:
----------------
int(7)
int(7)
Actual result:
--------------
Warning: file_get_contents(ftp://...@ftp.example.com/file#1.txt) [<a
href='function.file-get-contents'>function.file-get-contents</a>]: failed to open
stream: FTP server reports 550 /file : The system cannot find the path specified. in...
int(0)
int(7)
------------------------------------------------------------------------
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