Edit report at https://bugs.php.net/bug.php?id=63253&edit=1
ID: 63253
Updated by: felipe@php.net
Reported by: schicker03 at gmail dot com
Summary: class member access using __invoke() in php5.4
-Status: Assigned
+Status: Open
-Type: Bug
+Type: Feature/Change Request
Package: Scripting Engine problem
Operating System: MacOSX 10.8
PHP Version: 5.4.7
-Assigned To: felipe
+Assigned To:
Block user comment: N
Private report: N
New Comment:
This is not a bug... but a feature request.
Previous Comments:
------------------------------------------------------------------------
[2012-10-10 14:12:37] schicker03 at gmail dot com
Description:
------------
As described in that link, class member access is available as of PHP 5.4
>>http://www.php.net/manual/en/migration54.new-features.php,
>>>>Class member access on instantiation has been added, e.g. (new Foo)->bar().
My PHP Version is 5.4.0 (not 5.4.7 like showing above, but there`s no choice for
5.4.0 so I used 5.4.7)
See the sample script, why is that sample not working ?
(new Foo('bar'))();
I don´t know if this is really a bug, but i believe it should work.
best
schicker03
Test script:
---------------
<?php
class Foo
{
/** @var string */
protected $bar;
/**
* @param string $bar
*/
public function __construct($bar)
{
$this->bar = $bar;
}
/**
* @return null
*/
public function __invoke()
{
echo $this->bar;
}
}
//works as expected, using __invoke()
$foo = new Foo('bar');
$foo();
//works as expected, calling __invoke()
(new Foo('bar'))->__invoke();
//invalid, but why !? Should work from my point of view
(new Foo('bar'))();
Expected result:
----------------
Expected Result whould be the string bar 3 times:
barbarbar
------------------------------------------------------------------------
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Edit this bug report at https://bugs.php.net/bug.php?id=63253&edit=1