Bug #64018 [Opn]: missing elements from the result set when using foreach with referencing $value

Edit report at https://bugs.php.net/bug.php?id=64018&edit=1 ID: 64018 User updated by: potyo dot ada at gmail dot com Reported by: potyo dot ada at gmail dot com Summary: missing elements from the result set when using foreach with referencing $value Status: Open Type: Bug Package: Scripting Engine problem Operating System: Ubuntu 12.10 PHP Version: Irrelevant Block user comment: N Private report: N New Comment: Tested using 5.3.5 and 5.4.10 versions Previous Comments: ------------------------------------------------------------------------ [2013-01-18 11:40:40] potyo dot ada at gmail dot com Description: ------------ If we try to change the array elements in one foreach loop using referenced $value, and in a second foreach loop remove some elements from the array, then the resulting array misses some element, some elements are duplicated, or simply nothing is removed, depending on that, which element we want to remove from the array in the second loop. Test script: --------------- $a=array(array('a'=>'11', 'aa'=>'22'), array('a'=>'33', 'aa'=>'44'), array('a'=>'55', 'aa'=>'66')); foreach ($a as &$v) // if we use $k=>$v here { $v['c']='99'; // and $a[$k]['c']='99' here, then it produces the expected result } foreach ($a as $k=>$v) { if ($v['aa']=='22') { unset($a[$k]); // } } print_r($a); Expected result: ---------------- Array ( [1] => Array ( [a] => 33 [aa] => 44 [c] => 99 ) [2] => Array ( [a] => 33 [aa] => 44 [c] => 99 ) ) Actual result: -------------- Array ( [1] => Array ( [a] => 33 [aa] => 44 [c] => 99 ) [2] => Array ( [a] => 55 [aa] => 66 [c] => 99 ) ) ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=64018&edit=1