Req #63359 [Com]: Defining a interface const with value of another constant triggers fatal error
| From: | jan dot kahoun at heureka dot cz | Date: | Wed, 22 May 2013 08:36:01 +0000 |
| Subject: | Req #63359 [Com]: Defining a interface const with value of another constant triggers fatal error | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-179069@lists.php.net to get a copy of this message | ||
Edit report at https://bugs.php.net/bug.php?id=63359&edit=1
ID: 63359
Comment by: jan dot kahoun at heureka dot cz
Reported by: maciej dot sz at gmail dot com
Summary: Defining a interface const with value of another
constant triggers fatal error
Status: Open
Type: Feature/Change Request
Package: Scripting Engine problem
Operating System: Linux
PHP Version: 5.4.8
Block user comment: N
Private report: N
New Comment:
Same problem with PHP 5.4.13 on CentOS release 6.4 (Final)
Previous Comments:
------------------------------------------------------------------------
[2013-01-14 11:07:21] edmond at inbox dot ru
Some problem: OS Windows 7 64-bits
------------------------------------------------------------------------
[2012-11-19 11:59:16] aharvey@php.net
Automatic comment from SVN on behalf of aharvey
Revision: http://svn.php.net/viewvc/?view=revision&revision=328423
Log: Warn about configure options that were deprecated in 5.3 and removed in 5.4.
Fixes doc bug #63359 (configure: WARNING: unrecognized options:
--enable-zend-multibyte).
------------------------------------------------------------------------
[2012-11-14 16:37:32] maciej dot sz at gmail dot com
How come a feature request? This is an obvious bug.
------------------------------------------------------------------------
[2012-11-14 15:21:33] laruence@php.net
change to feature request.
------------------------------------------------------------------------
[2012-11-14 14:52:29] dagguh at gmail dot com
This is especially painful when you are trying to work your way around lack of
class literal.
<?
namespace pl\dagguh\building;
class Kitchen implements Room {
const CLASS_NAME = "pl\\dagguh\\building\\Kitchen";
}
interface Room {
const CLASS_NAME = "pl\\dagguh\\building\\Room";
}?>
--------
You often need the class name for mocking frameworks.
------------------------------------------------------------------------
The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
https://bugs.php.net/bug.php?id=63359
--
Edit this bug report at https://bugs.php.net/bug.php?id=63359&edit=1