Bug #66917 [Com]: __set will not called in any situation

Edit report at https://bugs.php.net/bug.php?id=66917&edit=1 ID: 66917 Comment by: daniel dot chobe at nextiraone dot eu Reported by: daniel dot chobe at nextiraone dot eu Summary: __set will not called in any situation Status: Not a bug Type: Bug Package: Class/Object related Operating System: Irrelevant PHP Version: Irrelevant Block user comment: N Private report: N New Comment: Ok, I don't like this behavior, it is not logical. But anyway is it possible to update the documentation to describe this behavior to other people? Previous Comments: ------------------------------------------------------------------------ [2014-03-17 16:21:24] requinix@php.net That is true: when your __set() defined $name on the instance it was no longer "not defined" and thus the method will not be called for it in the future. If you don't want that to happen then don't define $name on the instance - stick it in an array or something. ------------------------------------------------------------------------ [2014-03-17 14:04:32] daniel dot chobe at nextiraone dot eu Description: ------------ The __set Magic Method will be called only one time if the variable is not defined. If the variable defined, __set will not called anymore, but the value is changed. See Example. Test script: --------------- <?php class test { public function __set($name, $value) { echo "Set $name to $value" . PHP_EOL; $this->$name = $value; } } $test = new test(); $test->foo = 1; echo 'Foo: ' . $test->foo . PHP_EOL; $test->foo = 2; echo 'Foo: ' . $test->foo . PHP_EOL; Expected result: ---------------- Set foo to 1 Foo: 1 Set foo to 2 Foo: 2 Actual result: -------------- Set foo to 1 Foo: 1 Foo: 2 ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=66917&edit=1