Req #47967 [Fbk->NoF]: array_clone - would also clone referenced objects

Edit report at https://bugs.php.net/bug.php?id=47967&edit=1 ID: 47967 Updated by: php-bugs@lists.php.net Reported by: r at dumb dot ro Summary: array_clone - would also clone referenced objects -Status: Feedback +Status: No Feedback Type: Feature/Change Request Package: Class/Object related Operating System: Irrelevant PHP Version: 5.2.9 Private report: N New Comment: No feedback was provided. The bug is being suspended because we assume that you are no longer experiencing the problem. If this is not the case and you are able to provide the information that was requested earlier, please do so and change the status of the bug back to "Re-Opened". Thank you. Previous Comments: ------------------------------------------------------------------------ [2014-04-16 23:31:36] levim@php.net Are you still interested in pursuing this? ------------------------------------------------------------------------ [2009-04-14 19:12:47] code at dumb dot ro One more thing I'd like to add: In order for this function to work properly and for cloning in general, I think PHP would need 2 different kinds of references, an implicit and an explicit one. Basically if I'd say $arr = array(new Obj()); it would use an implicit reference, therefore when I'll clone the array the object would also be cloned. If I say $arr = array(&new Obj()); that would be an explicit reference so I want the array to be an array of references and therefore the referenced object won't be cloned. This subject should be discussed in detail before implementation, because it has huge ramifications, basically the whole cloning process could be changed. ------------------------------------------------------------------------ [2009-04-14 14:44:49] r at dumb dot ro Description: ------------ When you pass an array of objects to a function (not by reference) and you modfiy one of the objects in the array, the main array (the referenced objects) will be modified. This wasn't a problem until objects got passed by reference by default. Reproduce code: --------------- $class A { } $a = new A(); $a->x = 10; $arr = array($a); function foo($arr) { $arr[0]->x = 1; } foo($arr); print_r($arr); Expected result: ---------------- the expected result would be 10 Actual result: -------------- since the array is internally using references for the stored objects the result will be 1. to fix this I wrote a function that clones the array properly and I'm calling the function like this: foo(array_clone($arr)); ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=47967&edit=1