#18825 [Fbk->Bgs]: Ignoring formatting (Read to understand)
| From: | sniper@php.net | Date: | Wed, 11 Sep 2002 16:52:24 +0000 |
| Subject: | #18825 [Fbk->Bgs]: Ignoring formatting (Read to understand) | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-19169@lists.php.net to get a copy of this message | ||
ID: 18825
Updated by: sniper@php.net
Reported By: php@awpti.org
-Status: Feedback
+Status: Bogus
Bug Type: Output Control
Operating System: Linux
PHP Version: 4.1.2
New Comment:
Sorry, but the bug system is not the appropriate forum for asking
support questions. Your problem does not imply a bug in PHP itself.
For a list of more appropriate places to ask for help using PHP,
please visit http://www.php.net/support.php
Thank you for your interest in PHP.
Previous Comments:
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[2002-08-09 04:27:23] rasmus@php.net
Somewhere along the line you are doing something silly. Put up a .phps
of your actual code somewhere. Or show us a small self-contained
script that illustrates this. I'm 99.999% sure this is user error.
But I'll be nice and leave this in feedback mode for a little while.
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[2002-08-09 02:26:13] php@awpti.org
Here's the code snippet:
<span>Links</span> - <?php print '<a
href="'.$base_dir.'/awlinks.php">.:back:.</a> --
<strong>'._cat_title($getcat).'</strong>'; ?>
Here's the result:
Links - Cartoons<a href="/awlinks/awlinks.php">.:back:.</a> --
<strong></strong></td>
Cartoons SHOULD be between <strong></strong> (That's the point of
_cat_title()
-- here's the code for _cat_title
function _cat_title($getcat) {
$res = mysql_query("SELECT * FROM LinksCatalog WHERE ID =
'$getcat'");
$row = mysql_fetch_assoc($res);
$title = $row['LinkGroup'];
return $title;
}
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Edit this bug report at http://bugs.php.net/?id=18825&edit=1