Bug #69601 [Opn->Nab]: Miss array key access after json_decode
| From: | cmb@php.net | Date: | Fri, 08 May 2015 11:18:16 +0000 |
| Subject: | Bug #69601 [Opn->Nab]: Miss array key access after json_decode | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-192580@lists.php.net to get a copy of this message | ||
Edit report at https://bugs.php.net/bug.php?id=69601&edit=1
ID: 69601
Updated by: cmb@php.net
Reported by: turin dot tomsk at gmail dot com
Summary: Miss array key access after json_decode
-Status: Open
+Status: Not a bug
Type: Bug
Package: JSON related
Operating System: Linux
PHP Version: 5.5.24
-Assigned To:
+Assigned To: cmb
Block user comment: N
Private report: N
New Comment:
Sorry, but your problem does not imply a bug in PHP itself. For a
list of more appropriate places to ask for help using PHP, please
visit http://www.php.net/support.php as this bug system
is not the
appropriate forum for asking support questions. Due to the volume
of reports we can not explain in detail here why your report is not
a bug. The support channels will be able to provide an explanation
for you.
Thank you for your interest in PHP.
Read the section on "Converting to array" in the manual[1]. What
you actually want to do is
$q = json_decode($s, true);
[1] <http://php.net/manual/en/language.types.array.php#language.types.array.casting>
Previous Comments:
------------------------------------------------------------------------
[2015-05-08 10:07:26] turin dot tomsk at gmail dot com
Description:
------------
When json_encode array and json_decode it, can't get access to array key of object and generate
PHP Notice.
Test script:
---------------
<?php
$a = [1 => 2];
$s = json_encode($a);
$b = @json_decode($s);
$q = (array)$b;
var_dump($q[1]); // PHP Notice: Undefined offset: 1 in php shell code on line 1
?>
------------------------------------------------------------------------
--
Edit this bug report at https://bugs.php.net/bug.php?id=69601&edit=1