Bug #69784 [Com]: bad variable reference
Edit report at https://bugs.php.net/bug.php?id=69784&edit=1
ID: 69784
Comment by: artur at salonstron dot pl
Reported by: artur at salonstron dot pl
Summary: bad variable reference
Status: Open
Type: Bug
Package: Variables related
Operating System: irrelevant
PHP Version: 5.6.9
Block user comment: N
Private report: N
New Comment:
Customer servers running on different Linux distributions.
Previous Comments:
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[2015-06-10 10:10:50] artur at salonstron dot pl
Currently I'm using: PHP Version 5.5.11 on windows. On most of my clients servers php version
is 5.2-5.5. Recently, one of the servers has been updated to version 5.6.9 and the difference is
just there.
See this example: http://phpbug.studiostron.eu/ its
output of the same script + phpversion()
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[2015-06-10 09:49:56] nikic@php.net
According to http://3v4l.org/L8GsZ this behavior has stayed the
same for all PHP versions - apart from a short regression interval in PHP 7. Are you sure the code
you tested on older versions wasn't in some way different?
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[2015-06-10 09:43:54] artur at salonstron dot pl
in previous versions of php script worked differently. The variable $d was assigned to different
array with unmodified IAP.
It seems to me that it is a a bug because if I wanted to return a reference to the array, which is
inside a function test() I would done it differently.
Sorry for my english, I hope that everybody understands what I mean.
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[2015-06-10 09:21:32] nikic@php.net
Sorry, I'm not sure I see what the issue is here. In test() you're modifying the internal
array pointer (IAP) of $a and then returning $a (including the modified IAP). Then in the main
script you assign this to $d (still with modified IAP that is at the end of the array) and try to
iterate further with it - which fails. Isn't this how it is supposed to work?
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[2015-06-09 11:25:57] artur at salonstron dot pl
Description:
------------
In the example below, the variable $d is assigned a reference to a local variable $a (in function
test) despite the fact that variable was not returns by reference.
To fix this, you must either before returning the $a use the reset(), or inside test() use another
variable.
Test script:
---------------
<?php
$a = array (
1=>"a",
2=>"b",
3=>"c"
);
$d = test($a);
echo "d:<br />";
while(list($key, $val)=each($d)) {
echo $val." ";
}
function test($a) {
while(list($key, $val)=each($a)) {
$a[$key] = $val . "t3";
}
return $a;
}
Expected result:
----------------
d:
at3 bt3 ct3
Actual result:
--------------
d:
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Edit this bug report at https://bugs.php.net/bug.php?id=69784&edit=1
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