Bug #74871 [Com]: if statement behavior
| From: | rtheunissen@php.net | Date: | Fri, 07 Jul 2017 00:01:33 +0000 |
| Subject: | Bug #74871 [Com]: if statement behavior | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-209874@lists.php.net to get a copy of this message | ||
Edit report at https://bugs.php.net/bug.php?id=74871&edit=1
ID: 74871
Comment by: rtheunissen@php.net
Reported by: johovich at yande dot ru
Summary: if statement behavior
Status: Open
Type: Bug
Package: *General Issues
Operating System: Linux version 2.6.32-531.23.3.lv
PHP Version: 7.1.7
Block user comment: N
Private report: N
New Comment:
This is not a bug.
if ($condition) is the same as if ($condition == true),
so in the second part of your test script if you changed the strict !== to
!=, you would get the same results.
So you're effectively saying if (($pos = 0) == true) which will drop to the
else.
Previous Comments:
------------------------------------------------------------------------
[2017-07-06 23:51:22] johovich at yande dot ru
Description:
------------
If i use set var inside 'if' statement condition $var = '0' is the same as $var
= false. But it is not the same. So if assign var to function that returns 0 as integer or 0 as
string 'if' statement condition works as false.
Test script:
---------------
//In this script you can see, that set var value to 0 is equal to boolean false
//applied to if statement. There is no diff between integer 0 or string '0'
if($pos = 0){
$pos++;
} else {
$pos = 0;
}
var_dump($pos);
//$pos is not boolean false, so it should do if condition true, but it's not
//to make this work well i use this
$pos = 0;
if($pos !== false){
$pos++;
} else {
$pos = 0;
}
var_dump($pos);
------------------------------------------------------------------------
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Edit this bug report at https://bugs.php.net/bug.php?id=74871&edit=1