#19600 [Fbk->Opn]: <xsl:include> requires full pathname

ID: 19600 User updated by: tony@marston-home.demon.co.uk Reported By: tony@marston-home.demon.co.uk -Status: Feedback +Status: Open Bug Type: XSLT related Operating System: Windows XP PHP Version: 4.2.3 New Comment: That works, thank you. Problem solved. Previous Comments: ------------------------------------------------------------------------ [2002-10-03 04:28:57] k.schroeder@php.net Please try http://www.php.net/manual/en/function.xslt-set-base.php to solve your problem. Regards, Kai ------------------------------------------------------------------------ [2002-09-25 13:53:10] tony@marston-home.demon.co.uk I am using Windows XP, PHP 4.2.3, Apache 1.3.26 I am using XSLT to produce HTML output. The code I use is as follows: $arg_buffer = array("/xml" => $xml_string, "/xslt" => $xsl_string); $result = xslt_process($xp, "arg:/xml", "arg:/xslt", NULL, $arg_buffer, $params))) My xsl file contains as 'include' statement which points to a file which exists in the same folder as the PHP script. I initially tried it as <xsl:include href="pagination.xsl"/> but it produced this error: 'arg:/pagination.xsl' not found (error code: 65) I then tried it with <xsl:include href="file://pagination.xsl"/> and got this error: cannot open file '/pagination.xsl' (error code: 4) It only works if I enter the full path, as in <xsl:include href="file://c:/blah/blah/blah/pagination.xsl"/> It is very inconvenient to have to specify the full pathname in every <xsl:include> statement. Should it not first look in the current directory? This may be more of an enhancement request than a bug. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=19600&edit=1