#19838 [Opn->Bgs]: Oct 27, 2002
| From: | msopacua@php.net | Date: | Wed, 09 Oct 2002 21:26:59 +0000 |
| Subject: | #19838 [Opn->Bgs]: Oct 27, 2002 | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-21988@lists.php.net to get a copy of this message | ||
ID: 19838
Updated by: msopacua@php.net
Reported By: danielkim@rogers.com
-Status: Open
+Status: Bogus
Bug Type: Date/time related
Operating System: Windows 2000
PHP Version: 4.2.0
New Comment:
We are happy to tell you that you just discovered Daylight Savings
Time. For more information see:
http://webexhibits.org/daylightsaving/b.html
$ php4/sapi/cli/php -f ./data.php
86400
Start at: Oct 20 '02
Oct 21 '02 00:00:00 (1035151200 - 1)
Oct 22 '02 00:00:00 (1035237600 - 2)
Oct 23 '02 00:00:00 (1035324000 - 3)
Oct 24 '02 00:00:00 (1035410400 - 4)
Oct 25 '02 00:00:00 (1035496800 - 5)
Oct 26 '02 00:00:00 (1035583200 - 6)
Oct 27 '02 00:00:00 (1035669600 - 7)
Oct 27 '02 23:00:00 (1035756000 - 8)
Oct 28 '02 23:00:00 (1035842400 - 9)
Previous Comments:
------------------------------------------------------------------------
[2002-10-09 16:16:07] danielkim@rogers.com
<?php
// Arbitrary dates to find out a day value in int
$dayX = strtotime('Jan 2 2002') - strtotime('Jan 1 2002');
$dayY = strtotime('April 28 1999') - strtotime('April 27 1999');
if ($dayX == $dayY){
$aDay = $dayX; //$aDay = 86400;
$date[0] = strtotime('Oct 24 2002');
print date("M j 'y", $date[0]);
print '<br>';
for ($i=1; $i<10; $i++){
$date[$i] = $date[$i-1] + $aDay;
print date("M j 'y", $date[$i]);
print '<br>';
}
}
?>
The code prints
Oct 24 '02
Oct 25 '02
Oct 26 '02
Oct 27 '02
Oct 27 '02
Oct 28 '02
Oct 29 '02
Oct 30 '02
Oct 31 '02
Nov 1 '02
------------------------------------------------------------------------
[2002-10-09 16:07:42] danielkim@rogers.com
<?php
// Arbitrary dates to find out a day value in int
$dayX = strtotime('Jan 2 2002') - strtotime('Jan 1 2002');
$dayY = strtotime('April 28 1999') - strtotime('April 27 1999');
if ($dayX == $dayY){
$aDay = $dayX; //$aDay = 86400;
$date[0] = strtotime('Oct 20 2002');
print date("M j 'y", $date[0]);
print '<br>';
for ($i=1; $i<10; $i++){
$date[$i] = $date[$i-1] + $aDay;
print date("M j 'y", $date[$i]);
print '<br>';
}
}
?>
The code prints
Oct 20 '02
Oct 21 '02
Oct 22 '02
Oct 23 '02
Oct 24 '02
Oct 25 '02
Oct 26 '02
Oct 27 '02
Oct 27 '02
Oct 28 '02
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=19838&edit=1