Req #77776 [Com]: if inline goto

Edit report at https://bugs.php.net/bug.php?id=77776&edit=1 ID: 77776 Comment by: xxalfa at gmail dot com Reported by: xxalfa at gmail dot com Summary: if inline goto Status: Duplicate Type: Feature/Change Request Package: *General Issues PHP Version: Irrelevant Block user comment: N Private report: N New Comment: Reply to requinix@php.net Please explain in more detail why PHP would die? If the counterpart can not be found, the program will simply continue running at that point. My wish is it, the counterpart is not found, goto returns false. Reply to spam2 at rhsoft dot net My idea of a possible area of application is in the direction of sequencer processing. With goto I jump to the program part and with popen, for example, opens two sub-process and monitors the runtime - while the main program is waiting for an event capture. Depending on the status of the sub-process, the main program will evaluate the status and take further steps. It would have to be determined what happens in case of: condition of success, termination condition and timeout. Previous Comments: ------------------------------------------------------------------------ [2019-03-21 23:42:46] spam2 at rhsoft dot net the better question is which sane code needs goto to begin with, it was nice as i where a young child coding on a C64 in basic but even not relevant 20 years ago in visual basic ------------------------------------------------------------------------ [2019-03-21 23:39:34] requinix@php.net If there is no matching label then PHP will die. goto will never return. ------------------------------------------------------------------------ [2019-03-21 23:34:40] xxalfa at gmail dot com We are not talking about the same thing yet. The difference is well known to me, I ask more the question, why is "goto" can not be an expression. What would have to be done for "goto" to say the other side is there (or not), I'll jump (or not). I imagine a milder "goto" feature, which asks politely, can I jump? The current "goto" function absolutely wants to have a counterpart. ------------------------------------------------------------------------ [2019-03-21 22:38:12] requinix@php.net If you want to continue the RFC process on your other request, read the How To you were linked that tells you exactly what you need to do. If you need an explanation of the difference between a statement and an expression, try StackOverflow. ------------------------------------------------------------------------ [2019-03-21 22:35:10] requinix@php.net Duplicate of request #72589. ------------------------------------------------------------------------ The remainder of the comments for this report are too long. To view the rest of the comments, please view the bug report online at https://bugs.php.net/bug.php?id=77776 -- Edit this bug report at https://bugs.php.net/bug.php?id=77776&edit=1