Req #62778 [Fbk->NoF]: pre-increment operator produces rvalue rather than lvalue

From: Date: Sun, 01 Sep 2019 04:22:08 +0000
Subject: Req #62778 [Fbk->NoF]: pre-increment operator produces rvalue rather than lvalue
References: 1  Groups: php.bugs 
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Edit report at https://bugs.php.net/bug.php?id=62778&edit=1 ID: 62778 Updated by: php-bugs@lists.php.net Reported by: dexen dot devries at gmail dot com Summary: pre-increment operator produces rvalue rather than lvalue -Status: Feedback +Status: No Feedback Type: Feature/Change Request Package: Variables related PHP Version: 5.4.6RC1 Private report: N New Comment: No feedback was provided. The bug is being suspended because we assume that you are no longer experiencing the problem. If this is not the case and you are able to provide the information that was requested earlier, please do so and change the status of the bug back to "Re-Opened". Thank you. Previous Comments: ------------------------------------------------------------------------ [2019-08-21 13:20:28] nikic@php.net Is there any motivation for allowing this? PHP is pretty consistent about not returning references from assignment-like operations -- the only one that does so is the proper by-reference assignment (=&). I don't see any reason why we would want to change this. ------------------------------------------------------------------------ [2012-08-08 11:50:17] dexen dot devries at gmail dot com Description: ------------ Result of pre-increment (also pre-decrement) operator is a value (rvalue') rather than a reference to variable (lvalue'). This prevents assigning result of the operator to reference, or passing it by reference. There is no apparent reason for such limitation; the operator only applies to variables (never to other expressions), and PHP core supports references. The requested behavior is similar to C++ (result of pre-increment operator is reference); the current behavior mimics C (result of pre-increment operator is an rvalue). Test script: --------------- $a = 0; $b = 0; $c = 0; function foo(&$v) { $v = $v + 1; } ++$a; foo($a); var_dump($a); foo(++$b); var_dump($b); $b =& ++$c; var_dump($c); Expected result: ---------------- $a === 2 $b === 2 $c === 1 Actual result: -------------- $a === 2 Strict Standards: Only variables should be passed by reference $b === 1 PHP Parse error: syntax error, unexpected '++' (T_INC) ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=62778&edit=1

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