Bug #78795 [Opn->Nab]: Preg_replace does not always replace

Edit report at https://bugs.php.net/bug.php?id=78795&edit=1 ID: 78795 Updated by: cmb@php.net Reported by: markem at sim1 dot us Summary: Preg_replace does not always replace -Status: Open +Status: Not a bug Type: Bug Package: Regexps related Operating System: Windows 10 PHP Version: 7.3.11 -Assigned To: +Assigned To: cmb Block user comment: N Private report: N New Comment: Sorry, but your problem does not imply a bug in PHP itself. For a list of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php as this bug system is not the appropriate forum for asking support questions. Due to the volume of reports we can not explain in detail here why your report is not a bug. The support channels will be able to provide an explanation for you. Thank you for your interest in PHP. For a start, see <https://3v4l.org/AsuaR>. Previous Comments: ------------------------------------------------------------------------ [2019-11-08 03:01:12] markem at sim1 dot us Description: ------------ --- From manual page: https://php.net/function.preg-replace --- I was working on correcting a function by dawidgarus at gmail dot com. Got it working (yeah!). But then decided to write my own and expand upon it. That was when I ran into this problem: If you use preg_replace, the "replace" string can not use the $x or ${x} within another variable (like an array). This generates an error. Test script: --------------- function bc() { $argv = func_get_args(); $cmd = $argv[0]; $cmd = preg_replace( "/\$(\d+)/", $argv[$1], $cmd ); return( $cmd ); } $a = bc( "sqrt($1*$1+$2*$2)", 3, 5 ); Expected result: ---------------- $a should equal "sqrt(3*3+5*5)" Actual result: -------------- Notice: Undefined variable: i in C:\Users\Mark\My Programs\PHP\lib\bcd.php on line ### ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=78795&edit=1