Req #81359 [Opn->Nab]: assignement in function parameter

Edit report at https://bugs.php.net/bug.php?id=81359&edit=1 ID: 81359 Updated by: cmb@php.net Reported by: rh at hofercomputing dot ch Summary: assignement in function parameter -Status: Open +Status: Not a bug Type: Feature/Change Request Package: Compile Failure Operating System: windows PHP Version: 8.0.9 -Assigned To: +Assigned To: cmb Block user comment: N Private report: N New Comment: > but $x is a variable, and this was accepted in recent versions. It was supported, but a notice/strict warning was thrown as of PHP 5.1.2, and the code didn't do what you intended[1], because the expression $x=18 actually evaluates to 18. As of PHP 8.0.0, you get an Error exception instead. That is explicitly mentioned in the migration guide[2]: | Some "Only variables should be passed by reference" notices have | been converted to "Argument cannot be passed by reference" | exception. And the manual proper states[3]: | It is an error to pass a value as argument which is supposed to | be passed by reference. [1] <https://3v4l.org/Pklt2> [2] <https://www.php.net/manual/en/migration80.incompatible.php> [3] <https://www.php.net/manual/en/functions.arguments.php#functions.arguments.by-reference> Previous Comments: ------------------------------------------------------------------------ [2021-08-14 11:19:34] rtrtrtrtrt at dfdfdfdf dot dfd fixed version of your code: $x=18; a($x); ------------------------------------------------------------------------ [2021-08-14 09:11:49] rh at hofercomputing dot ch Description: ------------ function a(&$p){ $p++; } a($x=18); this produces "Uncaught Error: a(): Argument #1 ($p) cannot be passed by reference in " but $x is a variable, and this was accepted in recent versions. ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=81359&edit=1