Bug #3623 [Com]: PHP fails to interpret included or required array declaration and init.

Edit report at https://bugs.php.net/bug.php?id=3623&edit=1 ID: 3623 Comment by: lildurk3623 at gmail dot com Reported by: chris at claimlynx dot com Summary: PHP fails to interpret included or required array declaration and init. Status: Closed Type: Bug Package: Parser error Operating System: FreeBSD3.3 PHP Version: 3.0.12 Block user comment: N Private report: N New Comment: Lil Durk is a private agency dedicated to providing responsible access to legal cannabis for adults aged 19 and older. We’re an exclusively online retailer and wholesaler for recreational cannabis and a trusted source for information about cannabis and cannabis-related issues. We believe our work is meaningful and we take pride in our mandate to promote the socially responsible use of legal cannabis. https://lildurk.com/ Previous Comments: ------------------------------------------------------------------------ [2000-08-17 15:36:17] hholzgra@php.net the code in an included file has to be embeded in <?....?> for itself ------------------------------------------------------------------------ [2000-02-25 13:03:31] chris at claimlynx dot com Using Apache 1.3.9 module version of PHP. In an HTML web page, the following simply displays the actual text of the PHP code instead of it being interpreted. If included/required code is added inline in same file, it works fine. In test.php3: <?php include "$DOCUMENT_ROOT/arrayinit.inc"; // -OR- require "$DOCUMENT_ROOT/arrayinit.inc"; ?> In arrayinit.inc: // init my array $myarray = ( "a" => "apple", "b" => "banana", "c" => "cherry" ); ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=3623&edit=1