[php-src] Issue #7733: variable losing reference after being set in function

Issue: https://github.com/php/php-src/issues/7733 Author: rbro ### Description I ran into the below scenario, which might be correct, but it wasn't something I expected, and I wanted to make sure it's the correct behavior. In the below scenario, why do $a and $b lose their references, but $c retains the reference? I was expecting $a and $b to keep their references like $c does. It's almost like they are being passed by value since they revert to their original value even though they are passed by reference. Is this correct behavior? https://3v4l.org/uHaGq Thanks for your help. The following code: ```php <?php $a = null; $b = 'test'; $c = null; $test1 = function() use (&$a, &$b, &$c) { $value = 1; $a = &$value; $b = &$value; $c = array( 'c' => &$value, ); }; $test1(); echo 'a: '; var_dump($a); echo 'b: '; var_dump($b); echo 'c: '; var_dump($c); exit; ``` Resulted in this output: ``` a: NULL b: string(4) "test" c: array(1) { ["c"]=> int(1) } ``` But I expected this output instead: ``` a: int(1) b: int(1) c: array(1) { ["c"]=> int(1) } ``` ### PHP Version PHP 7.4.26 ### Operating System _No response_