#20222 [Opn->Bgs]: mssql_free_result():
| From: | kalowsky@php.net | Date: | Sat, 02 Nov 2002 20:23:38 +0000 |
| Subject: | #20222 [Opn->Bgs]: mssql_free_result(): | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-23958@lists.php.net to get a copy of this message | ||
ID: 20222
Updated by: kalowsky@php.net
Reported By: boccara@netvision.net.il
-Status: Open
+Status: Bogus
Bug Type: MSSQL related
Operating System: win 2k server SBS
PHP Version: 4.2.3
New Comment:
Not enough information was provided for us to be able
to handle this bug. Please re-read the instructions at
http://bugs.php.net/how-to-report.php
If you can provide more information, feel free to add it
to this bug and change the status back to "Open".
Thank you for your interest in PHP.
Can you give us the full error message as well?
Previous Comments:
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[2002-11-02 13:46:05] boccara@netvision.net.il
I 've got this warning for a query that works, I don't understand why.
PHP Warning: mssql_free_result(): 18 is not a valid MS SQL-result
resource in ...
here the code:
$strSQL = " SELECT REF_PRODUIT FROM PRODUITS WHERE ACTUEL = 1 AND
REF_EDITEUR = '$pEditeur' AND REF_PRODUIT ='".$tabCol[0]."'";
$iQuery2 = dbQuery($iConnect, $strSQL) ;
echo $iQuery2;
dbFetch($iQuery2, $tabref);
dbFreeResult($iQuery2);
here the echo of iQuery2:
Resource id #9
Resource id #12
Resource id #15
Resource id #18
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Edit this bug report at http://bugs.php.net/?id=20222&edit=1