[php-src] Issue #9195: php -F command line option shows the error "Could not open input file:"

Issue: https://github.com/php/php-src/issues/9195 Author: ricardosdl ### Description Executing php cli like this: php -i | php -F foo.php This is the content of foo.php: ```php <?php echo $argn, PHP_EOL; ``` Resulted in this output: ``` ... $_SERVER['argc'] => 0 $_ENV['ALLUSERSPROFILE'] => C:\ProgramData $_ENV['APPDATA'] => C:\Users\ricardo.lima\AppData\Roaming $_ENV['CG_BOOST_ROOT'] => C:\Program Files (x86)\Embarcadero\RAD Studio\7.0\include\boost_1_39 Could not open input file: foo.php ``` The output of the command is cut short and the error message is the last thing in the output. But I expected this output instead: ``` ... PHP License This program is free software; you can redistribute it and/or modify it under the terms of the PHP License as published by the PHP Group and included in the distribution in the file: LICENSE This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. If you did not receive a copy of the PHP license, or have any questions about PHP licensing, please contact license@php.net. ``` ### PHP Version PHP 8.1.8 (cli) (built: Jul 5 2022 23:10:34) (NTS Visual C++ 2019 x64) Copyright (c) The PHP Group Zend Engine v4.1.8, Copyright (c) Zend Technologies ### Operating System Windows 10