Bug #16050 Updated: does not set name variable in <input type="image" name="do"..>

ID: 16050 Updated by: derick@php.net -Summary: does not set name variable in <input type="image" name="do"..> Reported By: gleitner@marinercapital.com -Status: Open +Status: Bogus Bug Type: Scripting Engine problem Operating System: linux PHP Version: 4.1.2 New Comment: not a bug really... see if $do_x and/or $do_y are set ($doit will certainly not be set, you're using 'do'). Derick Previous Comments: ------------------------------------------------------------------------ [2002-03-13 17:10:10] gleitner@marinercapital.com i meant to say does not set the variable $doit also, the button is located at a protected site, NOT at www.xxx.com (that links to a porn site, which was not the intention) ------------------------------------------------------------------------ [2002-03-13 17:03:12] gleitner@marinercapital.com the scripting engine does not set $doit when i submit <input type="image" name="do" src="http://www.xxx.com/buttons/fund_off.jpg"> sample code to test: <? if (isset($doit)) print "yes"; else print "no"; ?> <form name="form1" method="post" action="./test.php"> <input type="image" name="doit" src="http://www.xxx.com/buttons/fund_off.jpg"> </form> when i click on the image, i still get a "no" ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=16050&edit=1