#20406 [Bgs]: defined() does not work properly within function or class

ID: 20406 User updated by: fredbird@contactoffice.net Reported By: fredbird@contactoffice.net Status: Bogus Bug Type: Variables related Operating System: Windows XP PHP Version: 4.2.0 New Comment: About NAME and NOM : this is a translation problem only (NOM being the french word for NAME). This piece of code is just an example to show the bug : please read NAME and NOM as the same constant. I tested this code and it print _really_ "value". As for the name of an undefined constant being treated as the string value of the name, i didn't knew about it. It just makes me wonder more how are we supposed to check if a constant is defined within a function or a class, and why we can't althought we can access the value of this constant. I can't help but thinking that this _is_ a bug. Previous Comments: ------------------------------------------------------------------------ [2002-11-13 07:35:44] tix@php.net Btw. your example is wrong, you check 'NOM' instead of 'NAME'. Another thing in your script is "defined(NOM)". You should write "define('NOM')". And the last: you can't use "if (NAME)" for a replacement of "if (defined('NAME'))". In this case NAME is evaluted to the string 'NAME'. The condition is always TRUE :) Think about it. ------------------------------------------------------------------------ [2002-11-13 07:32:26] cynic@php.net first, read the code you gave us again. it can't produce the output you claim it does. it will output "NOM", and possibly an E_NOTICE. clearly, this is not a test case for your perceived problem. second, i don't know what EasyPHP is, but maybe you should file a PR with its vendor? ------------------------------------------------------------------------ [2002-11-13 07:20:19] fredbird@contactoffice.net I was not asking for support nor help. I know that i can replace "if (defined(NAME))" by "if (NAME)", for example. I may be wrong about the place where i reported this bug. But i wonder how you can explain that this is a good behavior for defined() : how can a constant have a value that you can have access to and not be defined ? ------------------------------------------------------------------------ [2002-11-13 04:58:33] derick@php.net Sorry, but your problem does not imply a bug in PHP itself. For a list of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php as this bug system is not the appropriate forum for asking support questions. Thank you for your interest in PHP. ------------------------------------------------------------------------ [2002-11-13 04:39:32] fredbird@contactoffice.net The function defined() always return false within a function or class, although the value of the constant is still available. the code : <?php define(NAME, "value"); function f() { if (defined(NOM)) echo "NOM is defined"; echo NOM; } f(); ?> will print "value" only. Currently tested with EasyPHP running with a Windows XP computer. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=20406&edit=1