#21435 [Csd->Opn]: termination when calling mysql_info()

ID: 21435 Updated by: nicos@php.net Reported By: drews@laborox.com -Status: Closed +Status: Open Bug Type: MySQL related Operating System: Windows 2000 PHP Version: 4.3.0 Assigned To: georg Previous Comments: ------------------------------------------------------------------------ [2003-01-06 18:13:37] gothfather@zotteltier.de I think this is not the solution ... i just downloaded the 22:30 Snapshot of Jan 01st (stabel 4.3.0) and I get a SegVault calling mysql_info($vk). calling mysql_info() (without parameter) seems to work! ------------------------------------------------------------------------ [2003-01-05 15:11:57] georg@php.net This bug has been fixed in CVS. In case this was a PHP problem, snapshots of the sources are packaged every three hours; this change will be in the next snapshot. You can grab the snapshot at http://snaps.php.net/. In case this was a documentation problem, the fix will show up soon at http://www.php.net/manual/. In case this was a PHP.net website problem, the change will show up on the PHP.net site and on the mirror sites in short time. Thank you for the report, and for helping us make PHP better. ------------------------------------------------------------------------ [2003-01-05 14:25:37] georg@php.net verified... assigned to myself ------------------------------------------------------------------------ [2003-01-05 13:11:03] derick@php.net As you have MSVC, would you be able to provide a stack trace (which you should have on the screen when you see those assembler code lines)? Derick ------------------------------------------------------------------------ [2003-01-05 13:09:21] drews@laborox.com when calling mysql_info() apache 1.3.24 terminates with an error: "The instruction at "0x100c1588" referenced memory at "0x0000000a". the memory could not be "read" [ok/debug]. M$ debug gives "100C1588 cmp byte ptr [eax+8],7" script when calling: <?php $vk = mysql_pconnect($host, $user, $pass) or die (); mysql_select_db($database, $vk) or die (); $sql = "select * from user"; $result = mysql_query($sql, $vk); if($result) { while ($row = mysql_fetch_array($result)) { echo $row[0]; } } echo mysql_info($vk); ?> regards, -Wolfgang ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=21435&edit=1