#21569 [Com]: PHP can't set cookies after a test with an unset variable
| From: | ElfQrin at ElfQrin dot com | Date: | Mon, 13 Jan 2003 22:47:54 +0000 |
| Subject: | #21569 [Com]: PHP can't set cookies after a test with an unset variable | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-29917@lists.php.net to get a copy of this message | ||
ID: 21569
Comment by: ElfQrin@ElfQrin.com
Reported By: ElfQrin@ElfQrin.com
Status: Bogus
Bug Type: Unknown/Other Function
Operating System: Windows 2000 only
PHP Version: 4.3.0
New Comment:
Why does it affect only Windows 2000, while the very same PHP version
with the same php.ini file works fine on Windows 98 ? And it works
fine on Linux too?
To make it clearer, the "workarounds" are needed only if the scripts
run under Windows 2000, so that the example script returns "1" on
Windows 2000 and "3" on Windows 98 or Linux.
Previous Comments:
------------------------------------------------------------------------
[2003-01-13 16:37:48] sniper@php.net
There's really no bug here. You're getting a notice about unitialized
variable which causes the rest of the headers not to get send. Try
adding 'error_reporting(0);' in the beginning of your script..
------------------------------------------------------------------------
[2003-01-13 10:48:18] ElfQrin@ElfQrin.com
Workaround #2:
At the beginning og your script, "declare" any possibly unset variable
that will be invoked:
if (!isset($test)) {$test="";}
------------------------------------------------------------------------
[2003-01-13 10:07:12] ElfQrin@ElfQrin.com
Workaround (which doesn't mean this bug shouldn't be fixed):
To perform tests:
if (!isset($test) || $test=="") { echo ""; }
To set a variable:
$a=""; if (isset($test)) { $a=$test; }
------------------------------------------------------------------------
[2003-01-13 10:05:53] ElfQrin@ElfQrin.com
I've found out that the problem is not limited to tests. It happens
every time you invoke an unset variable before than setting a cookie.
In the previous example, try
$a = $test;
instead of
if ($test=="") { echo ""; }
and the setcookie won't work as well.
------------------------------------------------------------------------
[2003-01-13 10:03:29] ElfQrin@ElfQrin.com
This is a shortest example:
<?
# $test="";
setcookie("debug","1",0,"","");
if ($test=="") { echo ""; }
setcookie("debug","3",0,"","");
echo "Cookie: [".$_COOKIE["debug"]."] (HIT RELOAD)<BR>";
?>
------------------------------------------------------------------------
The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
http://bugs.php.net/21569
--
Edit this bug report at http://bugs.php.net/?id=21569&edit=1