#21912 [Ver]: getimagesize() on remote images fails sometimes..

ID: 21912 Updated by: helly@php.net Reported By: tozz@kijkt.tv Status: Verified Bug Type: GetImageSize related Operating System: Linux PHP Version: 4.3.1-dev New Comment: I suppose ther is another problem :-) When i download the image and put it on one of my local servers it works: [marcus@zaphod php4-HEAD]$ php -r 'print_r(getimagesize($argv[1]));' -- http://zaphod.boerger.de/php/ext/exif/test/bug21912.jpg Array ( [0] => 389 [1] => 500 [2] => 2 [3] => width="389" height="500" [bits] => 8 [channels] => 3 [mime] => image/jpeg ) [marcus@zaphod php4-HEAD]$ php -r 'var_dump(getimagesize($argv[1]));' -- http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg bool(false) Previous Comments: ------------------------------------------------------------------------ [2003-01-28 13:52:36] tozz@kijkt.tv Yes, it has indeed something to do with the image. If I take another image it works fine! But there must be some difference in the PHP versions since the 2nd pictures only works with PHP 4.1.2, and not with the latest PHP version. ------------------------------------------------------------------------ [2003-01-28 13:26:00] michael.mauch@gmx.de php -r '$size = getimagesize("http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg"); print_r($size); echo "\n";' works without problems here (PHP 4.3.0), while php -r '$size = getimagesize("http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg"); print_r($size); echo "\n";' prints nothing. ImageMagick's "identify" sees some strange ipct data in the second image; probably these make getimagesize() misbehave. ------------------------------------------------------------------------ [2003-01-27 17:25:35] sniper@php.net I can reproduce this with latest stable CVS (4.3.1-dev) It does work if the image is local..but not if it's remote. ------------------------------------------------------------------------ [2003-01-27 16:12:37] tozz@kijkt.tv Hallo, I have a weird problem, which I think is a bug. The following script works with PHP 4.1.2 (I know, very outdated), but DOES NOT work with PHP 4.3.0: <? error_reporting (E_ALL); $foto="http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg"; $image_size=getimagesize($foto); $width=$image_size[0]; $height=$image_size[1]; $type=$image_size[2]; print ("<img src='$foto'>\n"); print ("<p>\n"); print ("width: $width; height: $height; type: $type<br>\n"); print ("<p>\n"); $foto="http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg"; $image_size=getimagesize($foto); $width=$image_size[0]; $height=$image_size[1]; $type=$image_size[2]; print ("<img src='$foto'>\n"); print ("<p>\n"); print ("width: $width; height: $height; type: $type<br>\n"); ?> The problem is : The first image works fine, it shows the height, width and type. However, the information about the second image is only beeing displayed if using PHP 4.1.2. With PHP 4.3.0 no information is beeing displayed. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=21912&edit=1