#22886 [Opn->Bgs]: preg_replace $0 and $1
| From: | iliaa@php.net | Date: | Wed, 26 Mar 2003 15:55:48 +0000 |
| Subject: | #22886 [Opn->Bgs]: preg_replace $0 and $1 | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-36478@lists.php.net to get a copy of this message | ||
ID: 22886
Updated by: iliaa@php.net
Reported By: ekomhadi at yahoo dot com
-Status: Open
+Status: Bogus
Bug Type: PCRE related
Operating System: Linux
PHP Version: 4.3.0
New Comment:
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to
report
a bug at http://bugs.php.net/how-to-report.php
$0 and $1 are not valid variable names and in case of regex they are
treated like $0 (entire matched string) and $1 1st matched element.
Previous Comments:
------------------------------------------------------------------------
[2003-03-25 22:23:08] ekomhadi at yahoo dot com
I'm using PHP 4.3.0
I found problem when using preg_replace(..)
string $0 and $1 will mess up and not replace correctly
also $N with N is Integer will not appear. If the character after the
dollar sign is not a number, it works as expected.
Here is my code:
<?php
/*** PHP START***/
// Found: 26-03-2003
$strBuffer=
'
<pre>
----------------------
preg_replace() bug???
----------------------
<LOOP>
[NUMBER] [MESG]
</LOOP>
----------------------
</pre>
';
$strNumber = 123456789;
$strMesg = "text with $0 and $1 string";
$Patttern = "/<LOOP>(.*?)<\/LOOP>/is";
preg_match($Patttern, $strBuffer, $arrTag);
$strData = str_replace("[NUMBER]", $strNumber, $arrTag[1]);
$strData = str_replace("[MESG]", $strMesg, $strData);
$strBuffer= preg_replace($Patttern, $strData, $strBuffer);
echo $strBuffer;
/*** PHP END***/
?>
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=22886&edit=1