#22994 [Opn->Bgs]: if ( $something == "NAME") { print $something } prints "0"
| From: | rasmus@php.net | Date: | Mon, 31 Mar 2003 23:02:13 +0000 |
| Subject: | #22994 [Opn->Bgs]: if ( $something == "NAME") { print $something } prints "0" | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-36867@lists.php.net to get a copy of this message | ||
ID: 22994
Updated by: rasmus@php.net
Reported By: hermandepauw at hotmail dot com
-Status: Open
+Status: Bogus
Bug Type: Unknown/Other Function
Operating System: Red Hat Linux
PHP Version: 4.3.0
New Comment:
Use === if you want to check both type and value. The numerical value
of "NAME" is indeed 0, so if $something is 0 the condition will be
true.
Previous Comments:
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[2003-03-31 16:45:16] hermandepauw at hotmail dot com
if ( $something == "NAME") { print $something } prints "0"
the main problem is in the summary ... example code and source on
http://www.deparadox.be/php/ i don't know the
explain it in words so
get a view ... code is only ~10 lines
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Edit this bug report at http://bugs.php.net/?id=22994&edit=1