Bug #11725 Updated: Bitwise operators seems buggy

ID: 11725 Updated by: tcurdt@dff.st -Reported By: Pascal.Dufour@cdt.eu.int +Reported By: tcurdt@dff.st Status: Bogus Bug Type: Math related Operating System: Linux 2.2 PHP Version: 4.0.6 New Comment: Guys, guys, guys! I've read #7755 but sorry - this definitly *IS* a bug!! Signed or unsigned - doesn't matter. It's what a user expects to work! If you ever programmed in Assembler you should know that signed or unsigned doesn't really matter (for this case) It's only a different interpretation on 32-bit number! Using GMP is not an real alternative. As a matter of fact 45 & 0xFFFFFFFF is 45!! As well as 45 & -1 is 45!! Previous Comments: ------------------------------------------------------------------------ [2001-06-28 13:10:50] sniper@php.net Like in the #7755 was suggested, for now, use GMP functions. ------------------------------------------------------------------------ [2001-06-27 15:14:49] Pascal.Dufour@cdt.eu.int I suppose you make ref to this: >[2000-11-23 07:41:55] stas@php.net > Still not working, possibly won't for some time - since PHP > numbers are 32-bits signed, so they don't work well as > 32-bit unsigned. >[2000-12-12 05:56:20] stas@php.net > I suspend this bug since PHP has no good solution for it in > the foreseeable future. Please use GMP functions for this. >[2001-05-13 05:33:17] derick@php.net > This is not a bug, so closing. Is there any way to work with unsigned number ? The goal is to do things like this (in a clean way): $timestamp = time(); $buf .= chr(($timestamp & 0xff000000) >> 24); $buf .= chr(($timestamp & 0xff0000) >> 16); $buf .= chr(($timestamp & 0xff00) >> 8); $buf .= chr($timestamp & 0xff); then compute some hash... Do you intend to provide such a 'feature' in a future release of PHP. I understand you do not consider this to be a 'bug', since this is part of the design of PHP. But, at least it is a missing 'feature'. When one work with hex numbers he does no want to handle the sign (in most cases) because the goal is to work at the bit level and not at the 'number' level. ------------------------------------------------------------------------ [2001-06-27 12:25:27] sniper@php.net See bug #7755 for reason why this is not bug. ------------------------------------------------------------------------ [2001-06-27 04:16:00] Pascal.Dufour@cdt.eu.int I have a problem with bitwise operator: The following script: <? printf("%08x (should be 05CDEA00)<BR>", (0x05CDEA00 & 0xFFFFFFFF)); printf("%08x (should be FFFFFFFF)<BR>", (0x05CDEA00 | 0xFFFFFFFF)); ?> displays: 00000000 (should be 05CDEA00) -7a321600 (should be FFFFFFFF) It seems that the bitwise 'and' does not work at all, it always returns 0. I do no understant the result of the bitwise 'or', and why it is displayed prefixed by a minus sign. I have read the documentation and I think these are bugs... I hope I have not misunderstood the doc. Pascal. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=11725&edit=1