#26624 [Com]: cannot get the right value when i use + operator

ID: 26624 Comment by: benjcarson at digitaljunkies dot ca Reported By: mlsx at cie dot xtu dot edu dot cn Status: Open Bug Type: Math related Operating System: windows server 2003 PHP Version: 4.3.3 New Comment: I believe you need to put the math expression in parentheses because '.' and '+' have the same precedence. What is happening is that you end up adding the value 2 to the string "a+b=2". If I do: echo "a+b=".($a+$b)."<br>"; it comes out correctly. Previous Comments: ------------------------------------------------------------------------ [2003-12-15 02:45:01] mlsx at cie dot xtu dot edu dot cn Description: ------------ first i define a is 8 and b is 6. When i use echo "a+b=".$a+$b."<br>"; the MS IE show the result is 2. While i use echo "a+b="; echo $a+$b."<br>"; the result is correct! the same result when use "-" operator use a line command. but the result is correct when i use * and / i cannnot fix it! Reproduce code: --------------- <?php $a = 8; $b = 2; $c = 3; echo "a+b=".$a+$b."<br>"; echo "a-b=".$a-$b."<br>"; echo "a*b=".$a*$b."<br>"; echo "a/b=".$a/$b."<br>"; echo "a%c=".$a%$c."<br>"; echo "a++ is ".$a++; ?> Expected result: ---------------- 2 -2 a*b=16 a/b=4 a%c=2 a++ is 8 Actual result: -------------- a+b=10 a-b=6 a*b=16 a/b=4 a%c=2 a++ is 8 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=26624&edit=1