#26671 [Fbk->Opn]: SWITCH fails when DEFAULT statement included

ID: 26671 User updated by: memoimyself at yahoo dot com dot br Reported By: memoimyself at yahoo dot com dot br -Status: Feedback +Status: Open Bug Type: Scripting Engine problem Operating System: Windows 2000 SP 4 PHP Version: 4.3.4 New Comment: Yes, I am positive. In fact, I was getting this error when debugging a class I'd written. I then created a simple test script (which I posted here) by typing (not by copying and pasting) everything again, and the error came up again. If I comment out the "default:" line, everything works well. Damned if I know what's going on. :-) Previous Comments: ------------------------------------------------------------------------ [2003-12-19 18:43:08] eru@php.net Works fine for me, same system: D:\PHP>php test.php Content-type: text/html X-Powered-By: PHP/4.3.4 a D:\PHP> Are you sure, that you don't have some control-character or anything like that in your code? Please retest. ------------------------------------------------------------------------ [2003-12-19 16:07:32] memoimyself at yahoo dot com dot br Description: ------------ The "switch" statement fails when a "default" case is included, as in the example below. It makes no difference if there's a "break" at the end of the default case. I'm not leaving out any parentheses, braces or semi-colons. In fact, all you need to do in order to get the switch statement below to work is comment out the last two lines before the closing brace. Reproduce code: --------------- $test = 'a'; switch ($test) { case 'a': print 'a'; break; case 'b': print 'b'; break; default: print 'neither'; } Expected result: ---------------- String 'a' should be printed on screen. Actual result: -------------- Parse error: parse error, unexpected T_DEFAULT in D:\htdocs\Test\test.php on line 12 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=26671&edit=1