#27395 [Bgs->Opn]: arrays cannot be passed by value
ID: 27395
User updated by: jamesn at tocquigny dot com
Reported By: jamesn at tocquigny dot com
-Status: Bogus
+Status: Open
Bug Type: Scripting Engine problem
Operating System: redhat linux
PHP Version: 4.3.4
New Comment:
in response to papercrane, no i didn't mean
function theFunction(&$array)
(this would pass by reference...by default php is doing this)
By flagging my bug as bogus are you stating the proper behavior is to
always pass by reference? (Which isn't proper at all IMO nor that of
coworkers or anyone that's worked w/ c/c++)
Previous Comments:
------------------------------------------------------------------------
[2004-02-25 12:41:15] sniper@php.net
It works exactly how it's supposed to work.
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[2004-02-25 12:36:13] papercrane at reversefold dot com
I think you meant:
function theFunction(&$array)
Even with the & it still won't work for me.
------------------------------------------------------------------------
[2004-02-25 12:02:02] jamesn at tocquigny dot com
Description:
------------
There appears to be a problem with php that doesn't allow arrays to be
passed by value. The fix appears to be something similar to:
http://bugs.php.net/bug.php?id=6417
if (PZVAL_IS_REF(*p))
{
SEPARATE_ZVAL(p);
} else {
zval_add_ref(p);
}
It would appear that that logic is missing in one place or another. I
could not track it down myself. Code similar to this appears to be
copy/pasted in various places.
Reproduce code:
---------------
$array = array(1);
// This line makes the call to theFunction() act as if passed by ref.?
$reference =& $array[0];
echo $array[0], '<br>';
theFunction($array);
echo $array[0], '<br>';
function theFunction($array) {
$array[0] = 2;
}
Expected result:
----------------
you should get 1 and 1
Actual result:
--------------
instead you get 1 and 2!
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Edit this bug report at http://bugs.php.net/?id=27395&edit=1
Thread (10 messages)