#28870 [Opn]: mysqli_bind_result doesn't work with cloned objects

From: Date: Mon, 21 Jun 2004 21:53:25 +0000
Subject: #28870 [Opn]: mysqli_bind_result doesn't work with cloned objects
References: 1  Groups: php.bugs 
Request: Send a blank email to php-bugs+get-61181@lists.php.net to get a copy of this message
ID: 28870 User updated by: rodolfo at rodsoft dot org Reported By: rodolfo at rodsoft dot org Status: Open Bug Type: *Database Functions Operating System: linux 2.6.7 PHP Version: 5.0.0RC3 New Comment: A possible 'hack' that I've found is to bind the result to another variable before cloning, and just after that restore the bind to the original variable. This way the result is the expected one. It seems that there's a problem of how mysqli_bind_result stores the variable information while it is being cloned. Previous Comments: ------------------------------------------------------------------------ [2004-06-21 18:35:56] rodolfo at rodsoft dot org Description: ------------ If you pass to mysqli_bind_result a member variable of an object that will be cloned and modified multiple times, each modification happens in all cloned objects, as if they weren't cloned copies, but a single copy of the object. Reproduce code: --------------- <? /* Say you have a database called 'test' with one table called 'test' that has one column called 'a' */ $db = new mysqli('localhost'); $db->select_db('test'); $stmt = $db->prepare('SELECT a FROM test'); $stmt->execute(); $result = new stdclass; // Comment the next line to have the 'right' behaviour $stmt->bind_result($result->a); for($i = 0; $i<10; ++$i) { $result->a = $i; $results[] = clone $result; } foreach($results as $result) echo $result->a,"\n"; $db->close(); ?> Expected result: ---------------- 0 1 2 3 4 5 6 7 8 9 Actual result: -------------- 9 9 9 9 9 9 9 9 9 9 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=28870&edit=1

« previous php.bugs (#61181) next »