#28902 [Opn->Bgs]: String offset syntax can't be used on integers.

ID: 28902 Updated by: iliaa@php.net Reported By: todd at magnifisites dot com -Status: Open +Status: Bogus Bug Type: Strings related Operating System: All PHP Version: 4.3.8-dev New Comment: Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php This is intended behavior. Previous Comments: ------------------------------------------------------------------------ [2004-06-24 01:51:32] pollita@php.net It's not strlen() that's failing. It's the $number{$offset} syntax. I can see the argument for casting $number to a string when string offset syntax is used, but I'm not sure enough it's the right thing to do. ------------------------------------------------------------------------ [2004-06-23 23:23:40] todd at magnifisites dot com Description: ------------ The substr() function will convert an integer and return the correct results. Using strlen() returns NULL, it does not convert an integer to string so that the expected results are returned. Reproduce code: --------------- $string = '12345'; $number = 12345; print substr($number, -1) . '<br />'; // works fine print $string{strlen($string)-1} . '<br />'; works fine // This won't work, $number is not a string: print $number{strlen($number)-1} . '<br />'; // Now cast it as a string and it will: $number = (string)$number; print $number{strlen($number)-1} . '<br />'; Expected result: ---------------- I would expect PHP to automagically convert the integer to a string without having to cast it as string first. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=28902&edit=1