Bug #8290 Updated: allow func_*_arg?() functions as function parameters inside a function

ID: 8290 Updated by: jimw@php.net Reported By: cynic@mail.cz -Status: Analyzed +Status: Closed Bug Type: Feature/Change Request Operating System: * PHP Version: 4.0.3pl1 New Comment: the syntax in the original request works just fine. Previous Comments: ------------------------------------------------------------------------ [2000-12-18 12:56:47] waldschrott@php.net I thought of something like INTERNAL_PARAM_PASSTHROUGH, otherwise you would have to do bar(fung_get_arg(0),func_get_arg(1),func_get_arg(2)...) or bar(func_get_args()) and then in bar work with an array of args ------------------------------------------------------------------------ [2000-12-18 08:35:48] cynic@mail.cz no need for constants - func_get_arg() / func_get_args() does that. ------------------------------------------------------------------------ [2000-12-16 14:31:56] waldschrott@php.net agreed, maybe even (as a special case in function calls) some constant containing the desired argument from function1 eg. __arg0, __arg1 but I guess this would be a performance loss anyway using func_get_arg? in function calls makes sense sometimes ------------------------------------------------------------------------ [2000-12-16 02:46:32] cynic@mail.cz It'd be handy if one could do function foo() { ... $x = bar( func_get_arg( 0 ) ) ; ... } ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=8290&edit=1