#29686 [Opn->Bgs]: Bug when using foreach on an array that has been referenced before
| From: | helly@php.net | Date: | Sun, 15 Aug 2004 13:07:59 +0000 |
| Subject: | #29686 [Opn->Bgs]: Bug when using foreach on an array that has been referenced before | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-64631@lists.php.net to get a copy of this message | ||
ID: 29686
Updated by: helly@php.net
Reported By: swalk at prp dot physik dot tu-darmstadt dot de
-Status: Open
+Status: Bogus
Bug Type: Arrays related
Operating System: Linux
PHP Version: 5CVS-2004-08-15 (dev)
New Comment:
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to
report
a bug at http://bugs.php.net/how-to-report.php
.
Previous Comments:
------------------------------------------------------------------------
[2004-08-15 15:05:48] et@php.net
Please read properly before posting. And also read
http://www.php.net/foreach , especially the part with
"Note: Also note
that foreach operates on a copy of the specified array and not the array
itself."
And as was said, it only happens if you do $a =& $a; before the foreach
clause. If you don't do it, you get the expected result.
------------------------------------------------------------------------
[2004-08-15 14:55:40] jakub dot phpbug at horky dot net
I'm afraid that is caused just by the line
$a = "foo";
which re-sets the $a variable to string, so it is no longer an array
and can't be enumerated by next loop...
------------------------------------------------------------------------
[2004-08-15 12:37:33] swalk at prp dot physik dot tu-darmstadt dot de
Description:
------------
When using foreach with an array that has been referenced before, it
behaves oddly if you re-set the variable inside the loop - it loses the
array it originally worked on. That doesn't happen if you leave the line
creating the reference out.
Reproduce code:
---------------
<?php
$a = array(1,2,3);
$b =& $a; // this line causes the bug
// $a =& $a; does it too
foreach($a as $v) {
print "$v\n";
$a = "foo";
}
Expected result:
----------------
1
2
3
Actual result:
--------------
1
Warning: Invalid argument supplied for foreach() in /home/et/test.php
on line 4
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=29686&edit=1