#30294 [Bgs]: GregorianToJD returning value for date that does not exist

ID: 30294 User updated by: garrettblits at yahoo dot com Reported By: garrettblits at yahoo dot com Status: Bogus Bug Type: Calendar related Operating System: RedHat 8.0 PHP Version: 5.0.2 New Comment: I have checked the documentation and no where in it does it say anything about how overflows are handled. Including such advisments in the documentation could be usefull. Opinion: I do understand there are other functions to check dates prior to using a function like this one. However, it seems wrong to have a calendar function which returns anything but an error(false) when given a "bogus" date as input. Previous Comments: ------------------------------------------------------------------------ [2004-10-01 09:04:50] derick@php.net Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php This is consistent with how the other date functions handle overflows. ------------------------------------------------------------------------ [2004-09-30 22:05:31] garrettblits at yahoo dot com Description: ------------ This function (GregorianToJD) will return a value for a date that does not exist. Reproduce code: --------------- $x = GregorianToJD(02,29,1998); $y = JDToGregorian($x); echo "$x - $y"; Expected result: ---------------- Nothing or an error: 02/29/1998 does not exist Actual result: -------------- 2450874 - 3/1/1998 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=30294&edit=1